b^2-4b=12

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Solution for b^2-4b=12 equation:


Simplifying
b2 + -4b = 12

Reorder the terms:
-4b + b2 = 12

Solving
-4b + b2 = 12

Solving for variable 'b'.

Reorder the terms:
-12 + -4b + b2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + -4b + b2 = 0

Factor a trinomial.
(-2 + -1b)(6 + -1b) = 0

Subproblem 1

Set the factor '(-2 + -1b)' equal to zero and attempt to solve: Simplifying -2 + -1b = 0 Solving -2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1b = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1b = 0 + 2 -1b = 0 + 2 Combine like terms: 0 + 2 = 2 -1b = 2 Divide each side by '-1'. b = -2 Simplifying b = -2

Subproblem 2

Set the factor '(6 + -1b)' equal to zero and attempt to solve: Simplifying 6 + -1b = 0 Solving 6 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1b = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1b = 0 + -6 -1b = 0 + -6 Combine like terms: 0 + -6 = -6 -1b = -6 Divide each side by '-1'. b = 6 Simplifying b = 6

Solution

b = {-2, 6}

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